Combustion of $10 \ mL$ of a gaseous hydrocarbon gives $40 \ mL$ of $CO_2$ and $50 \ mL$ of water vapour under the same conditions. The molecular formula of the hydrocarbon is

  • A
    $C_4H_6$
  • B
    $C_4H_8$
  • C
    $C_3H_4$
  • D
    $C_4H_{10}$

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