Complete reaction of 2.0 , g of calcium (at. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) . Let the equivalent weight of metal $M = x$. According to the law of equivalence,the number of equivalents of metal reacted is equal to the numbe

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(D) . Let the equivalent weight of metal $M = x$. According to the law of equivalence,the number of equivalents of metal reacted is equal to the number of equivalents of $H_2$ gas produced. $(eq)_{Ca} = (eq)_{H_2} 	ext{ (from Ca)} = \frac{2.0}{20} = 0.1$ $(eq)_{M} = (eq)_{H_2} 	ext{ (from M)} = \frac{2.0}{x}$ Since the volume of gas produced is directly proportional to the number of equivalents under identical conditions: $\frac{(eq)_{Ca}}{(eq)_{M}} = \frac{V_{H_2} 	ext{ (from Ca)}}{V_{H_2} 	ext{ (from M)}}$ $\frac{0.1}{2.0/x} = \frac{1.125}{1.85}$ $\frac{0.1x}{2.0} = \frac{1.125}{1.85}$ $x = \frac{1.125 	imes 2.0}{1.85 	imes 0.1} = \frac{2.25}{0.185} \approx 12.16$ Thus,the equivalent weight of $M$ is approximately $12$.

Isotope	$\%$ Natural abundance	Molar mass
$^1H$	$99.985$	$1$
$^2H$	$0.015$	$2$

Complete reaction of $2.0 \, g$ of calcium (at. wt. $= 40$) with excess $HCl$ produces $1.125 \, L$ of $H_2$ gas. Complete reaction of the same quantity of another metal $M$ with excess $HCl$ produces $1.85 \, L$ of $H_2$ gas under identical conditions. The equivalent weight of $M$ is closest to

Similar Questions

$116 \ mg$ of a compound on vaporisation in a Victor Meyer's apparatus displaces $44.8 \ mL$ of air measured at $S.T.P.$ The molecular weight of the compound is

$5 \, mol$ of $AB_2$ weigh $125 \times 10^{-3} \, kg$ and $10 \, mol$ of $A_2B_2$ weigh $300 \times 10^{-3} \, kg$. The molar mass of $A$ $(M_A)$ and molar mass of $B$ $(M_B)$ in $kg \, mol^{-1}$ are:

The weight of a substance that occupies $22.4 \ L$ at $NTP$ is called its.....

Calculate the average atomic mass of hydrogen using the following data:

Isotope $\%$ Natural abundance Molar mass

$^1H$ $99.985$ $1$

$^2H$ $0.015$ $2$

Equivalent weight of crystalline oxalic acid is

Vedclass Test Series

Exam Paper Generator

Online Exam Module