Complete the following reactions:
$(1)$ Isopropyl bromide $\xrightarrow[{KOH, \Delta}]{{\text{alcoholic}}} X$ $\xrightarrow[{peroxide}]{{HBr}} Y$
$(2)$ $n$-propyl alcohol $\xrightarrow[{443 \ K}]{{\text{Conc. } H_2SO_4}} X$ $\xrightarrow{{HBr}} Y$

(N/A) For reaction $(1)$:
Isopropyl bromide $(CH_3-CH(Br)-CH_3)$ undergoes dehydrohalogenation with alcoholic $KOH$ to form propene $(CH_3-CH=CH_2)$ as $X$.
Propene reacts with $HBr$ in the presence of peroxide (Kharasch effect/anti-Markovnikov addition) to form $1$-bromopropane $(CH_3-CH_2-CH_2Br)$ as $Y$.
For reaction $(2)$:
$n$-propyl alcohol $(CH_3-CH_2-CH_2OH)$ undergoes dehydration with conc. $H_2SO_4$ at $443 \ K$ to form propene $(CH_3-CH=CH_2)$ as $X$.
Propene reacts with $HBr$ (Markovnikov addition) to form $2$-bromopropane $(CH_3-CH(Br)-CH_3)$ as $Y$.