Complete the following reaction: C_6H_5OH + A | vedclass

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Question

(A) The reaction between phenol $(C_6H_5OH)$ and an arenediazonium salt $(ArN_2^+Cl^-)$ in the presence of a base $(OH^-)$ is an electrophilic aromati

Vedclass · Accepted Answer

$p-hydroxyazobenzene$ derivative

Vedclass · Answer

(A) The reaction between phenol $(C_6H_5OH)$ and an arenediazonium salt $(ArN_2^+Cl^-)$ in the presence of a base $(OH^-)$ is an electrophilic aromatic substitution reaction known as coupling reaction. In this reaction,the diazonium cation acts as an electrophile and attacks the electron-rich phenol ring. Since the $-OH$ group is ortho/para-directing,the coupling primarily occurs at the para-position to form $p-hydroxyazobenzene$ derivatives $(Ar-N=N-C_6H_4-OH)$.

Acid	$pKa$
$(a)$ Phenol	$(i)$ $16$
$(b)$ $p$-Nitrophenol	$(ii)$ $0.78$
$(c)$ Ethanol	$(iii)$ $10$
$(d)$ Picric acid	$(iv)$ $7.1$

Complete the following reaction: $C_6H_5OH + ArN_2^+Cl^- \xrightarrow{OH^-} ?$

Similar Questions

Match the following $pKa$ values:
Acid $pKa$
$(a)$ Phenol $(i)$ $16$
$(b)$ $p$-Nitrophenol $(ii)$ $0.78$
$(c)$ Ethanol $(iii)$ $10$
$(d)$ Picric acid $(iv)$ $7.1$

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