Complete the following table.
Atomic Number
Mass Number
Number of Neutrons
Number of Protons
Number of Electrons
Name of the Atomic Species
$9$
-
$10$
-
-
-
$16$
$32$
-
-
-
sulphur
-
$24$
-
$12$
-
-
-
$2$
-
$1$
-
-
-
$1$
$0$
$1$
$0$
-
| Atomic Number | Mass Number | Number of Neutrons | Number of Protons | Number of Electrons | Name of the Atomic Species |
| $9$ | - | $10$ | - | - | - |
| $16$ | $32$ | - | - | - | sulphur |
| - | $24$ | - | $12$ | - | - |
| - | $2$ | - | $1$ | - | - |
| - | $1$ | $0$ | $1$ | $0$ | - |
(N/A) To complete the table,we use the following relationships:
$1$. $\text{Atomic Number} (Z) = \text{Number of Protons} = \text{Number of Electrons (in a neutral atom)}$.
$2$. $\text{Mass Number} (A) = \text{Number of Protons} + \text{Number of Neutrons}$.
$1$. $\text{Atomic Number} (Z) = \text{Number of Protons} = \text{Number of Electrons (in a neutral atom)}$.
$2$. $\text{Mass Number} (A) = \text{Number of Protons} + \text{Number of Neutrons}$.
| Atomic Number | Mass Number | Number of Neutrons | Number of Protons | Number of Electrons | Name of the Atomic Species |
| $9$ | $19$ | $10$ | $9$ | $9$ | Fluorine |
| $16$ | $32$ | $16$ | $16$ | $16$ | Sulphur |
| $12$ | $24$ | $12$ | $12$ | $12$ | Magnesium |
| $1$ | $2$ | $1$ | $1$ | $1$ | Deuterium |
| $1$ | $1$ | $0$ | $1$ | $0$ | Hydrogen ion |
Explore More
Similar Questions
An atom of an element has $2$ electrons in the $M$ shell, i.e., the third shell. What will be the atomic number of this element? Name this element. Find the valency of this element. Also, find the number of neutrons in the atom of this element (assume mass number is $24$).
Medium
View SolutionWhat are isobars? Give one example.
Easy
View SolutionState reasons for the following statements:
$(i)$ Some elements possess fractional atomic mass.
$(ii)$ Isotopes of an element have similar chemical properties.
$(iii)$ Noble gases are inert.
$(i)$ Some elements possess fractional atomic mass.
$(ii)$ Isotopes of an element have similar chemical properties.
$(iii)$ Noble gases are inert.
Easy
View SolutionGiven that a natural sample of iron $(Fe)$ has isotopes $_{26}^{54}Fe$,$_{26}^{56}Fe$,and $_{26}^{57}Fe$ in the ratios of $5\%$,$90\%$,and $5\%$ respectively. What will be the average atomic mass of iron $(Fe)$ (in $u$)?
Medium
View SolutionIn a sample of ethyl ethanoate $(CH_{3}COOC_{2}H_{5})$,the two oxygen atoms have the same number of electrons but different number of neutrons. Which of the following is the correct reason for it?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo