The complex formed during the brown ring test of nitrate $(NO_3^-)$ ion is:

  • A
    $[Fe(H_2O)_5NO]SO_4$
  • B
    $[Fe(H_2O)_5NO_3]SO_4$
  • C
    $[Fe(NH_3)_6]SO_4$
  • D
    $Na_3[Fe(NO_3)_6]$

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$FeSO_4$ solution mixed with $(NH_4)_2SO_4$ solution in $1:1$ molar ratio gives the test of $Fe^{2+}$ ion,but $CuSO_4$ solution mixed with aqueous ammonia in $1:4$ molar ratio does not give the test of $Cu^{2+}$ ion. Explain why?

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