The reaction between cyclobutylmagnesium chlo | vedclass

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Question

(A) The reaction involves a Grignard reagent (cyclobutylmagnesium chloride) and an alcohol (cyclobutanol). Grignard reagents are strong bases and reac

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Cyclobutane

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(A) The reaction involves a Grignard reagent (cyclobutylmagnesium chloride) and an alcohol (cyclobutanol). Grignard reagents are strong bases and react with compounds containing acidic protons,such as alcohols,to form an alkane and a magnesium salt. The reaction is: $C_4H_7MgCl + C_4H_7OH \rightarrow C_4H_8 + C_4H_7OMgCl$ Here,the cyclobutyl group $(C_4H_7^-)$ abstracts the acidic proton from the hydroxyl group of cyclobutanol to form cyclobutane $(C_4H_8)$. Therefore,the product $P$ is cyclobutane.

The reaction between cyclobutylmagnesium chloride and cyclobutanol is shown below. Identify the product $P$.

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