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(C) The reaction sequence is as follows:$1$. The starting material is a cyclopentane ring substituted with a carboxylic acid group and an amide group.

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(C) The reaction sequence is as follows:$1$. The starting material is a cyclopentane ring substituted with a carboxylic acid group and an amide group. Treatment with $KOBr$ (Hoffmann bromamide degradation) converts the $-CONH_2$ group into an $-NH_2$ group.$2$. This results in compound $(A)$,which is $3$-aminocyclopentanecarboxylic acid.$3$. Upon heating $(\Delta)$,the amino acid undergoes intramolecular cyclization (dehydration) to form a cyclic amide,known as a lactam.$4$. The resulting product $(B)$ is the cyclic lactam,which corresponds to option $C$.

Compound $(B)$ is

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