Compound X of molecular formula C_4H_6 takes | vedclass

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(D) The molecular formula $C_4H_6$ corresponds to the degree of unsaturation $2$. Ozonolysis of compound $Y$ yields only ethanoic acid $(CH_3COOH)$,wh

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All the three

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(D) The molecular formula $C_4H_6$ corresponds to the degree of unsaturation $2$. Ozonolysis of compound $Y$ yields only ethanoic acid $(CH_3COOH)$,which implies that $Y$ is $CH_3CH=CHCH_3$ (but$-2-$ene). All three given compounds,when treated with one equivalent of $H_2$ in the presence of $Pt$,can form $CH_3CH=CHCH_3$: $1$. $CH_2=CH-CH=CH_2 + H_2 \xrightarrow{Pt} CH_3CH=CHCH_3$ $2$. $CH_3C \equiv CCH_3 + H_2 \xrightarrow{Pt} CH_3CH=CHCH_3$ $3$. $CH_2=C=CHCH_3 + H_2 \xrightarrow{Pt} CH_3CH=CHCH_3$ Finally,$CH_3CH=CHCH_3 + O_3 \rightarrow 2CH_3COOH$. Therefore,all three compounds satisfy the given conditions.

Compound $X$ of molecular formula $C_4H_6$ takes up one equivalent of hydrogen in the presence of $Pt$ to form another compound $Y$,which on ozonolysis gives only ethanoic acid. The compound $X$ can be:

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