Compound A (C_3H_6O) undergoes the following | vedclass

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Question

(A) The compound $A$ $(C_3H_6O)$ reacts with $I_2 / NaOH$ (iodoform test),which indicates it is a methyl ketone. Thus,$A$ is acetone $(CH_3COCH_3)$.$1

Vedclass · Accepted Answer

$A = CH_3COCH_3$,$B = CHI_3$,$C = CH_3CH_2CH_3$

Vedclass · Answer

(A) The compound $A$ $(C_3H_6O)$ reacts with $I_2 / NaOH$ (iodoform test),which indicates it is a methyl ketone. Thus,$A$ is acetone $(CH_3COCH_3)$.$1$. Reaction with $I_2 / NaOH$ (Iodoform reaction):$CH_3COCH_3 + 3I_2 + 4NaOH \rightarrow CHI_3 (B) + CH_3COONa + 3NaI + 3H_2O$Here,$B$ is iodoform $(CHI_3)$.$2$. Reaction with $Zn-Hg / HCl$ (Clemmensen reduction):$CH_3COCH_3 + 4[H] \xrightarrow{Zn-Hg / HCl} CH_3CH_2CH_3 (C) + H_2O$Here,$C$ is propane $(CH_3CH_2CH_3)$.

Compound $A$ $(C_3H_6O)$ undergoes the following reactions to form $B$ and $C$. Identify $A$,$B$,and $C$.

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