Compound P (C_{8}H_{8}O) gives a red-orange p | vedclass

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(B) $1$. Compound $P$ $(C_{8}H_{8}O)$ reacts with $2,4-DNP$ reagent, which confirms the presence of a carbonyl group (aldehyde or ketone).$2$. It does

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(B) $1$. Compound $P$ $(C_{8}H_{8}O)$ reacts with $2,4-DNP$ reagent, which confirms the presence of a carbonyl group (aldehyde or ketone).$2$. It does not reduce Fehling's reagent, which indicates that $P$ is a ketone, not an aldehyde.$3$. The molecular formula $C_{8}H_{8}O$ corresponds to acetophenone $(C_{6}H_{5}COCH_{3})$.$4$. On drastic oxidation with chromic acid $(H_{2}CrO_{4})$, the alkyl group attached to the benzene ring is oxidized to a carboxylic acid group.$5$. Acetophenone $(C_{6}H_{5}COCH_{3})$ on oxidation yields benzoic acid $(C_{6}H_{5}COOH)$ as product $Q$.$6$. Benzoic acid $(Q)$ reacts with aqueous $NaHCO_{3}$ to produce effervescence due to the evolution of $CO_{2}$ gas.$7$. Therefore, $P$ is acetophenone and $Q$ is benzoic acid.

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