Identify compound B in the following reaction | vedclass

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(D) $1$. The reaction of cyclopentanone with hydroxylamine $(H_2NOH)$ at $pH = 4.5$ is a nucleophilic addition-elimination reaction that forms an oxim

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Piperidin$-2-$one

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(D) $1$. The reaction of cyclopentanone with hydroxylamine $(H_2NOH)$ at $pH = 4.5$ is a nucleophilic addition-elimination reaction that forms an oxime,which is compound $(A)$.$2$. Compound $(A)$ is cyclopentanone oxime.$3$. When cyclopentanone oxime $(A)$ is treated with an acid catalyst $(H^+ / \Delta)$,it undergoes the Beckmann rearrangement.$4$. The Beckmann rearrangement of a cyclic oxime results in the expansion of the ring by inserting a nitrogen atom,forming a cyclic amide (lactam).$5$. For cyclopentanone oxime,the ring expansion leads to the formation of a six-membered lactam,which is piperidin$-2-$one (also known as $\delta$-valerolactam),which is compound $(B)$.

Identify compound $B$ in the following reaction sequence:
Cyclopentanone $+ H_2NOH$ $\xrightarrow{pH = 4.5, \Delta} (A)$ $\xrightarrow{H^+ / \Delta} (B)$

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Identify compound $B$ in the following reaction sequence:Cyclopentanone $+ H_2NOH$ $\xrightarrow{pH = 4.5, \Delta} (A)$ $\xrightarrow{H^+ / \Delta} (B)$