Which of the following compounds can show bot | vedclass

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(A) To exhibit geometrical isomerism,the molecule must have restricted rotation (like a double bond) and the groups attached to each end of the double

Vedclass · Accepted Answer

$3-$methylcyclohexylidene-cyclohexane

Vedclass · Answer

(A) To exhibit geometrical isomerism,the molecule must have restricted rotation (like a double bond) and the groups attached to each end of the double bond must be different. To exhibit optical isomerism,the molecule must lack a plane of symmetry or center of inversion (i.e.,it must be chiral).$A$: $3$-methylcyclohexylidene-cyclohexane has a chiral center at the $3$-position of the first ring. The double bond provides restricted rotation,and since the two sides of the double bond are different (one side has a methyl group,the other is unsubstituted),it can show geometrical isomerism. Thus,it shows both.$B$: $4$-methylcyclohexylidene-cyclohexane has a plane of symmetry passing through the $4$-position of the first ring and the center of the second ring,making it achiral (no optical isomerism).$C$: This structure is highly substituted and symmetric,often leading to meso forms or lack of chirality depending on the specific stereoisomers.$D$: $1,4$-diphenylcyclohexane can show geometrical isomerism (cis/trans),but it does not possess a chiral center in its standard form.Therefore,the correct answer is $A$.

Which of the following compounds can show both optical as well as geometrical isomerism?

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