Compound (A) with molecular formula C_6H_{12} | vedclass

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(C) Compound $(A)$ has the molecular formula $C_6H_{12}O_3$. It gives a positive iodoform test,indicating the presence of a $CH_3C(=O)-$ group. It giv

Vedclass · Accepted Answer

$CH_3-C(=O)-CH_2-CH(OCH_3)_2$

Vedclass · Answer

(C) Compound $(A)$ has the molecular formula $C_6H_{12}O_3$. It gives a positive iodoform test,indicating the presence of a $CH_3C(=O)-$ group. It gives a negative Tollens' test,meaning it does not have a free aldehyde group. Upon treatment with water and a drop of $H_2SO_4$ (acidic hydrolysis),it gives a positive Tollens' test,which indicates that an aldehyde group is generated. This suggests that $(A)$ contains a protected aldehyde group,specifically an acetal. Structure $(c)$,$CH_3-C(=O)-CH_2-CH(OCH_3)_2$,contains a $CH_3C(=O)-$ group (positive iodoform test) and an acetal group $-CH(OCH_3)_2$. Acidic hydrolysis of the acetal group yields an aldehyde group $(-CHO)$,which gives a positive Tollens' test.

Compound $(A)$ with molecular formula $C_6H_{12}O_3$ gives a positive iodoform test and a negative Tollens' test. Upon treatment with water and a drop of $H_2SO_4$,it gives a positive Tollens' test. Compound $(A)$ is:

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