The concentration of $[CN^{-}]$ in $0.1 \, M \, HCN$ solution is: $(K_a = 4 \times 10^{-10})$

  • A
    $2.5 \times 10^{-6} \, M$
  • B
    $4.5 \times 10^{-6} \, M$
  • C
    $6.3 \times 10^{-6} \, M$
  • D
    $9.2 \times 10^{-6} \, M$

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