Consider a rubber ball freely falling from a | vedclass

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(B) For downward motion,the velocity is given by $v = -gt$. The velocity increases in the downward direction,resulting in a straight line between $v$

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(B) For downward motion,the velocity is given by $v = -gt$. The velocity increases in the downward direction,resulting in a straight line between $v$ and $t$ with a negative slope.Applying the equation of motion $y - y_0 = ut + \frac{1}{2}at^2$,we get $y - h = -\frac{1}{2}gt^2$,which simplifies to $y = h - \frac{1}{2}gt^2$. This represents a downward-opening parabola starting at $y = h$ at $t = 0$.For upward motion after the elastic collision,the velocity direction is reversed,and its magnitude remains the same. The velocity follows $v = u - gt$,where $u$ is the velocity just after the collision. As $t$ increases,$v$ decreases linearly with a negative slope.The height $y$ as a function of time for the upward motion follows $y = ut - \frac{1}{2}gt^2$,which is an upward-opening parabola segment. Combining these,the velocity-time graph shows a sawtooth pattern with negative slopes,and the height-time graph shows a series of parabolic arcs. Graph $B$ correctly represents these physical behaviors.

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