Consider a uniform electric field vec{E} = 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electric field is given by $\vec{E} = 3 	imes 10^3 \hat{k} 	ext{ N C}^{-1}$.Since the plane of the square is parallel to the $yz$-plane,its

Vedclass · Accepted Answer

zero

Vedclass · Answer

(A) The electric field is given by $\vec{E} = 3 	imes 10^3 \hat{k} 	ext{ N C}^{-1}$.Since the plane of the square is parallel to the $yz$-plane,its area vector $\vec{A}$ must be perpendicular to the $yz$-plane,which means it is directed along the $x$-axis.Therefore,the area vector is $\vec{A} = A \hat{i} = (0.2 	ext{ m})^2 \hat{i} = 0.04 \hat{i} 	ext{ m}^2$.The electric flux $\phi$ is defined as the dot product of the electric field and the area vector: $\phi = \vec{E} \cdot \vec{A}$.Substituting the values: $\phi = (3 	imes 10^3 \hat{k}) \cdot (0.04 \hat{i})$.Since the dot product of orthogonal unit vectors $\hat{k} \cdot \hat{i} = 0$,the flux is $\phi = 0 	ext{ N m}^2 	ext{ C}^{-1}$.

Consider a uniform electric field $\vec{E} = 3 \times 10^3 \hat{k} \text{ N C}^{-1}$. The electric flux of this field through a square of $20 \text{ cm}$ on a side whose plane is parallel to the $yz$-plane is $....... \text{ N m}^2 \text{ C}^{-1}$.

Similar Questions

Give characteristics of electric field lines.

$Assertion (A):$ $A$ charge $q$ is placed at a height $h/4$ above the center of a square of side $b$. The flux associated with the square is independent of the side length $b$.
$Reason (R):$ Gauss's law is independent of the size of the Gaussian surface.

What is the electric flux for Gaussian surface $A$ that encloses the charged particles in free space? [Given: $q_1 = -14 \text{ nC}, q_2 = 78.85 \text{ nC}, q_3 = -56 \text{ nC}$]

$A$ point charge $q$ is placed at a distance $\frac{a}{2}$ directly above the centre of a square of side $a$. The electric flux through the square is

$C_1$ and $C_2$ are two hollow concentric cubes enclosing charges $2Q$ and $3Q$ respectively as shown in the figure. The ratio of electric flux passing through $C_1$ and $C_2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module