Consider the following solutions:I. 1 M gluc | vedclass

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(B) The osmotic pressure $(\pi)$ is given by $\pi = i 	imes C 	imes R 	imes T$,where $i$ is the van't Hoff factor.For $I$ (glucose): $i = 1$,so $\p

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$IV$ is hypertonic to $I, II, III$

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(B) The osmotic pressure $(\pi)$ is given by $\pi = i 	imes C 	imes R 	imes T$,where $i$ is the van't Hoff factor.For $I$ (glucose): $i = 1$,so $\pi_I \propto 1$.For $II$ $(NaCl)$: $i = 2$,so $\pi_{II} \propto 2$.For $III$ (acetic acid in benzene): Acetic acid dimerizes in benzene,so $i For $IV$ $((NH_4)_3PO_4)$: $i = 4$,so $\pi_{IV} \propto 4$.Comparing the osmotic pressures: $\pi_{IV} > \pi_{II} > \pi_I > \pi_{III}$.Since $IV$ has the highest osmotic pressure,it is hypertonic to all other solutions.Therefore,the correct option is $B$.

Consider the following solutions:
$I$. $1 \ M$ glucose $(aq.)$
$II$. $1 \ M$ sodium chloride $(aq.)$
$III$. $1 \ M$ acetic acid in benzene
$IV$. $1 \ M$ ammonium phosphate $(aq.)$

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Consider the following solutions:$I$. $1 \ M$ glucose $(aq.)$$II$. $1 \ M$ sodium chloride $(aq.)$$III$. $1 \ M$ acetic acid in benzene$IV$. $1 \ M$ ammonium phosphate $(aq.)$