Consider the following molecules NH_3, PH_3, | vedclass

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(C) The boiling point of hydrides of Group $15$ elements follows the order: $PH_3 < AsH_3 < NH_3 < SbH_3$. $NH_3$ exhibits intermolecular hydrogen bon

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$SbH_3$ because of higher molecular weight

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(C) The boiling point of hydrides of Group $15$ elements follows the order: $PH_3 $NH_3$ exhibits intermolecular hydrogen bonding due to the high electronegativity and small size of the nitrogen atom,which gives it an abnormally high boiling point compared to $PH_3$ and $AsH_3$. However,as we move down the group from $PH_3$ to $SbH_3$,the molecular size and mass increase significantly,leading to stronger van der Waals forces of attraction. $SbH_3$ has the highest molecular mass among the given hydrides,resulting in the strongest van der Waals forces,which makes its boiling point higher than that of $NH_3$.

Consider the following molecules $NH_3, PH_3, AsH_3, SbH_3$. Which of the following has the highest boiling point?

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