Consider the following four reactions: $(I) C_6H_5-CHCl-CH_3 \xrightarrow{95\% \text{ acetone}, 5\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(II) C_6H_5-CHCl-CH_3 \xrightarrow{90\% \text{ acetone}, 10\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(III) C_6H_5-CHCl-CH_3 \xrightarrow{80\% \text{ acetone}, 20\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(IV) C_6H_5-CHCl-CH_3 \xrightarrow{100\% \text{ water}} C_6H_5-CH(OH)-CH_3$ Arrange these reactions in decreasing order of the proportion of inverted product and select the correct answer from the codes given below:
- A$I > II > III > IV$
- B$II > I > III > IV$
- C$III > II > I > IV$
- D$IV > III > II > I$
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Similar Questions
For the following reactions:
$CH_{3}CH_{2}CH_{2}Br + Z^{-} \xrightarrow[substitution]{k_s} CH_{3}CH_{2}CH_{2}Z + Br^{-}$
$CH_{3}CH_{2}CH_{2}Br + Z^{-} \xrightarrow[elimination]{k_e} CH_{3}CH=CH_{2} + HZ + Br^{-}$
where
$Z^{-} = CH_{3}CH_{2}O^{-} (A)$ or $(CH_{3})_{3}CO^{-} (B)$
$k_s$ and $k_e$ are,respectively,the rate constants for the substitution and elimination,and $\mu = \frac{k_s}{k_e}$,the correct option is:
$CH_{3}CH_{2}CH_{2}Br + Z^{-} \xrightarrow[substitution]{k_s} CH_{3}CH_{2}CH_{2}Z + Br^{-}$
$CH_{3}CH_{2}CH_{2}Br + Z^{-} \xrightarrow[elimination]{k_e} CH_{3}CH=CH_{2} + HZ + Br^{-}$
where
$Z^{-} = CH_{3}CH_{2}O^{-} (A)$ or $(CH_{3})_{3}CO^{-} (B)$
$k_s$ and $k_e$ are,respectively,the rate constants for the substitution and elimination,and $\mu = \frac{k_s}{k_e}$,the correct option is:
Which of the following compounds will undergo racemisation when hydrolysed by an aqueous $KOH$ solution?
$(i)$ $C_6H_5CH_2Cl$
$(ii)$ $CH_3CH_2CH_2Cl$
$(iii)$ $(CH_3)_2CHCH_2Cl$
$(iv)$ $CH_3CH(Cl)C_2H_5$
$(i)$ $C_6H_5CH_2Cl$
$(ii)$ $CH_3CH_2CH_2Cl$
$(iii)$ $(CH_3)_2CHCH_2Cl$
$(iv)$ $CH_3CH(Cl)C_2H_5$
MediumNEET 2014
View Solution$1,2-dichlorocyclopentane$ $\xrightarrow{1 \text{ equivalent } Mg, \text{ ether}} X$ $\xrightarrow{D_2O} Y;$
$Y$ is:
$Y$ is:
Difficult
View SolutionThe reaction of a mixture of two organic compounds with $Na$ in ether gives $isobutane$ as a product. The two chlorine compounds are:
Medium
View SolutionThe reaction of $1$-bromohexane with aqueous $NaOH$ solution follows the order
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