Consider the electronic configuration for neu | vedclass

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(C) $(i) \ 1s^22s^22p^63s^1$ is the ground state configuration of $Na$ $(Z=11)$.$(ii) \ 1s^22s^22p^64s^1$ is an excited state configuration of $Na$ $(

Vedclass · Accepted Answer

$(a) \ T, (b) \ T, (c) \ F, (d) \ T$

Vedclass · Answer

(C) $(i) \ 1s^22s^22p^63s^1$ is the ground state configuration of $Na$ $(Z=11)$.$(ii) \ 1s^22s^22p^64s^1$ is an excited state configuration of $Na$ $(Z=11)$.Statement $(a)$ is True: Energy is required to excite an electron from the $3s$ orbital to the $4s$ orbital.Statement $(b)$ is True: Both configurations have $11$ electrons,representing $Na$.Statement $(c)$ is False: Both represent the same element $(Na)$ in different energy states.Statement $(d)$ is True: The $3s$ electron is closer to the nucleus than the $4s$ electron,so it is more tightly bound and requires more energy to remove.

Similar Questions

The number of unpaired electrons in the excited state of carbon is equal to the number of unpaired electrons in which of the following?

The total number of electrons that can be accommodated in all the orbitals having principal quantum number $n = 2$ and azimuthal quantum number $l = 1$ is

If $n = 3$,which of the following values of $l$ is correct?

The electronic configuration of three elements $A$,$B$,and $C$ are given below. Stable form of $A$ may be represented by the formula:
$A : 1s^2, 2s^2, 2p^6$
$B : 1s^2, 2s^2, 2p^6, 3s^2, 3p^3$
$C : 1s^2, 2s^2, 2p^6, 3s^2, 3p^5$

Assertion : An orbital designated by $n = 3, l = 1$ has double dumb-bell shape.
Reason : It belongs to $p-$subshell.

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