Consider the equation y - y_1 = m(x - x_1). I | vedclass

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(D) The given equation is $y - y_1 = m(x - x_1)$.Since $m$ is fixed,all lines have the same slope $m$,which implies that all lines are parallel to eac

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$B$ and $C$ both

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(D) The given equation is $y - y_1 = m(x - x_1)$.Since $m$ is fixed,all lines have the same slope $m$,which implies that all lines are parallel to each other.For any line in this family,if we set $x = x_1$,the equation becomes $y - y_1 = m(x_1 - x_1)$,which simplifies to $y = y_1$.Thus,every line in the set intersects the vertical line $x = x_1$ at the point $(x_1, y_1)$.Since both statements $B$ and $C$ are correct,the correct option is $D$.

Consider the equation $y - y_1 = m(x - x_1)$. If $m$ and $x_1$ are fixed and different lines are drawn for different values of $y_1$,then:

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