Consider the figure and answer the questions $(i)$ to $(vi)$ given below.
$(i)$ Redraw the diagram to show the direction of electron flow.
$(ii)$ Is the silver plate the anode or cathode?
$(iii)$ What will happen if the salt bridge is removed?
$(iv)$ When will the cell stop functioning?
$(v)$ How will the concentration of $Zn^{2+}$ ions and $Ag^{+}$ ions be affected when the cell functions?
$(vi)$ How will the concentration of $Zn^{2+}$ ions and $Ag^{+}$ ions be affected after the cell becomes 'dead'?

(N/A) $(i)$ Electrons move from the $Zn$ electrode to the $Ag$ electrode.
$(ii)$ The silver plate acts as the cathode.
$(iii)$ The cell will stop functioning because the electrical circuit is broken.
$(iv)$ The cell stops functioning when equilibrium is attained,i.e.,$E_{cell} = 0$.
$(v)$ As the cell functions,the concentration of $Zn^{2+}$ ions increases due to the oxidation of $Zn$ at the anode,and the concentration of $Ag^{+}$ ions decreases due to the reduction of $Ag^{+}$ at the cathode.
$(vi)$ When the cell becomes 'dead' $(E_{cell} = 0)$,the system is at equilibrium,so the concentrations of $Zn^{2+}$ and $Ag^{+}$ ions will no longer change.