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(A) charged comb creates an electric field that exerts an attractive force on polar molecules due to their permanent dipole moment,causing them to def

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$6$

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(A) charged comb creates an electric field that exerts an attractive force on polar molecules due to their permanent dipole moment,causing them to deflect from their path.Nonpolar molecules do not possess a permanent dipole moment and are not significantly deflected by a charged comb.Let us analyze the polarity of the given compounds:$1$. $O_2$: Nonpolar (homonuclear diatomic molecule).$2$. $HF$: Polar (electronegativity difference).$3$. $H_2O$: Polar (bent geometry).$4$. $NH_3$: Polar (pyramidal geometry).$5$. $H_2O_2$: Polar (non-planar structure).$6$. $CCl_4$: Nonpolar (symmetrical tetrahedral geometry).$7$. $CHCl_3$: Polar (asymmetrical tetrahedral geometry).$8$. $C_6H_6$: Nonpolar (symmetrical planar structure).$9$. $C_6H_5Cl$: Polar (asymmetrical substitution on the benzene ring).Polar molecules are: $HF, H_2O, NH_3, H_2O_2, CHCl_3, C_6H_5Cl$.Total number of polar molecules = $6$.

Consider the following compounds in the liquid form:
$O_2, HF, H_2O, NH_3, H_2O_2, CCl_4, CHCl_3, C_6H_6, C_6H_5Cl$.
When a charged comb is brought near their flowing stream,how many of them show deflection as per the figure?

Similar Questions

Number of compounds/species from the following with non-zero dipole moment is. . . . . . $BeCl_2, BCl_3, NF_3, XeF_4, CCl_4, H_2O, H_2S, HBr, CO_2, H_2, HCl$

Which of the following molecules is non-polar in nature?

Which of the following statements is correct?

The correct order of dipole moment for the following molecules is:

Select the correct statement$(s)$.

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Consider the following compounds in the liquid form:$O_2, HF, H_2O, NH_3, H_2O_2, CCl_4, CHCl_3, C_6H_6, C_6H_5Cl$.When a charged comb is brought near their flowing stream,how many of them show deflection as per the figure?