Consider the following information (X = F or | vedclass

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Question

(C) From the provided image,the bond lengths are:
$a = 1.577 \ \mathring{A}, b = 1.534 \ \mathring{A}, c = 1.612 \ \mathring{A}, d = 1.543 \ \mathrin

Vedclass · Accepted Answer

$f > d > a > b$

Vedclass · Answer

(C) From the provided image,the bond lengths are:
$a = 1.577 \ \mathring{A}, b = 1.534 \ \mathring{A}, c = 1.612 \ \mathring{A}, d = 1.543 \ \mathring{A}, e = 1.643 \ \mathring{A}, f = 1.553 \ \mathring{A}, g = 2.19 \ \mathring{A}, h = 2.04 \ \mathring{A}$.
Comparing the values:
$g (2.19) > h (2.04) > e (1.643) > c (1.612) > a (1.577) > f (1.553) > d (1.543) > b (1.534)$.
Evaluating the options:
$A$. $g (2.19) > a (1.577) > d (1.543) > b (1.534)$ (Correct order)
$B$. $g (2.19) > e (1.643) > f (1.553) > b (1.534)$ (Correct order)
$C$. $f (1.553) > d (1.543) > a (1.577) > b (1.534)$ (Incorrect order,as $a > f$)
$D$. $c (1.612) > f (1.553) > d (1.543) > b (1.534)$ (Correct order)
Thus,option $C$ is the incorrect order.

Molecule	$P-X$ (axial) bond length / $P-X$ (equatorial) bond length
$PF_5$	$a / b$
$PF_4CH_3$	$c / d$
$PF_3(CH_3)_2$	$e / f$
$PCl_5$	$g / h$

Consider the following information $(X = F$ or $Cl)$:

Molecule $P-X$ (axial) bond length / $P-X$ (equatorial) bond length

$PF_5$ $a / b$

$PF_4CH_3$ $c / d$

$PF_3(CH_3)_2$ $e / f$

$PCl_5$ $g / h$

According to the given information,choose the incorrect order of bond lengths.

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Consider the following information $(X = F$ or $Cl)$: Molecule $P-X$ (axial) bond length / $P-X$ (equatorial) bond length $PF_5$ $a / b$ $PF_4CH_3$ $c / d$ $PF_3(CH_3)_2$ $e / f$ $PCl_5$ $g / h$ According to the given information,choose the incorrect order of bond lengths.