Consider the following reaction scheme and ch | vedclass

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(C) $1$. Hydroboration-oxidation of styrene gives $P$ ($2$-phenylethanol,$C_6H_5CH_2CH_2OH$).$2$. Oxidation of $P$ with $CrO_3/H_2SO_4$ gives phenylac

Vedclass · Accepted Answer

$Q$: $2-$chloro$-2-$phenylacetic acid,$R$: $3-$phenylpropanoic acid,$S$: $1-$indanone

Vedclass · Answer

(C) $1$. Hydroboration-oxidation of styrene gives $P$ ($2$-phenylethanol,$C_6H_5CH_2CH_2OH$).$2$. Oxidation of $P$ with $CrO_3/H_2SO_4$ gives phenylacetic acid $(C_6H_5CH_2COOH)$.$3$. $HVZ$ reaction $(Cl_2/Red \ P)$ on phenylacetic acid gives $Q$ ($2$-chloro$-2-$phenylacetic acid,$C_6H_5CHClCOOH$).$4$. $P$ $(C_6H_5CH_2CH_2OH)$ reacts with $SOCl_2$ to give $C_6H_5CH_2CH_2Cl$,followed by $NaCN$ to give $C_6H_5CH_2CH_2CN$,and hydrolysis gives $R$ ($3$-phenylpropanoic acid,$C_6H_5CH_2CH_2COOH$).$5$. Intramolecular Friedel-Crafts acylation of $R$ using $conc. \ H_2SO_4$ gives $S$ ($1$-indanone).

Consider the following reaction scheme and choose the correct option for the major products $Q$,$R$ and $S$.

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