Consider the following reaction sequence: CH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: Electrophilic addition of $HBr$ to $3,3$-dimethyl-$1$-butene involves a carbocation intermediate. The initially formed secondary carboca

Vedclass · Accepted Answer

$CH_3-C(CH_3)=C(CH_3)-CH_3$

Vedclass · Answer

(D) Step $1$: Electrophilic addition of $HBr$ to $3,3$-dimethyl-$1$-butene involves a carbocation intermediate. The initially formed secondary carbocation $CH_3-C(CH_3)_2-C^{+}H-CH_3$ undergoes a $1,2$-methyl shift to form a more stable tertiary carbocation $CH_3-C^{+}(CH_3)-CH(CH_3)_2$. $Br^{-}$ then attacks this carbocation to form $2$-bromo-$2,3$-dimethylbutane. Step $2$: Dehydrohalogenation with alcoholic $KOH$ (elimination) follows Zaitsev's rule,where the more substituted alkene is the major product. Thus,$2,3$-dimethyl-$2$-butene $(CH_3-C(CH_3)=C(CH_3)-CH_3)$ is formed as the major end product.

Consider the following reaction sequence:
$CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$
The major end product formed is:

Similar Questions

Reagent $(A)$ in the reaction is

For the following reactions,the major products are shown: $H_2C=CH-CH=CH_2$ $\xrightarrow[0^\circ C]{HBr} CH_2=CH-CH(Br)-CH_3$ $\xrightarrow{25^\circ C} Br-CH_2-CH=CH-CH_3$. These provide an example of $1$ control at low temperature and $2$ control at higher temperature.

On catalytic reduction $(H_2 / Pt)$,how many alkenes will give $n$-butane?

The number of alkene isomers with the molecular formula $C_4H_8$ is ....

Alkene $X$ $\xrightarrow[\Delta]{KMnO_4}$ (Butan$-2-$one) $+$ (Pentanoic acid). $X$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following reaction sequence: $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow[2. KOH, EtOH, \text{heat}]{1. HBr}$ The major end product formed is: