Consider the following reactions. Total numbe | vedclass

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(D) The reaction sequence is as follows:$1$. Glucose reacts with $HI/\Delta$ to form $n$-hexane.$2$. $n$-hexane undergoes aromatization in the presenc

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$18$

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(D) The reaction sequence is as follows:$1$. Glucose reacts with $HI/\Delta$ to form $n$-hexane.$2$. $n$-hexane undergoes aromatization in the presence of $V_2O_5$ at $773 \ K$ and high pressure to form benzene.$3$. Benzene reacts with benzoyl chloride in the presence of anhydrous $AlCl_3$ (Friedel-Crafts acylation) to form benzophenone $(Ph-CO-Ph)$.In the product, benzophenone $(C_{13}H_{10}O)$:- Each phenyl ring has $3$ $\pi$ bonds, so $2$ rings have $6$ $\pi$ bonds.- The $C=O$ group has $1$ $\pi$ bond.- Total $\pi$ bonds = $6 + 1 = 7$. Each $\pi$ bond contains $2$ electrons, so total $\pi$ electrons = $7 	imes 2 = 14$.- The oxygen atom in the $C=O$ group has $2$ lone pairs of electrons, which equals $2 	imes 2 = 4$ electrons.- Total number of electrons = $14 + 4 = 18$.

List-$I$	List-$II$
$A$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$	$a$. Gattermann-Koch reaction
$B$. $C_6H_5CH_3 \xrightarrow{CrO_2Cl_2} C_6H_5CHO$	$b$. Etard reaction
$C$. $C_6H_5CH_2Br + CH_3Br \xrightarrow{Na/ether} C_6H_5CH_2CH_3$	$c$. Wurtz-Fittig reaction
$D$. $C_6H_6 + (CH_3)_2C = CH_2 \xrightarrow{H_2SO_4} C_6H_5C(CH_3)_3$	$d$. Friedel-Crafts alkylation

Consider the following reactions. Total number of electrons in the $\pi$ bonds and lone pair of electrons in the product is:

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