Consider the following reactions:
$K_2Cr_2O_7$ $\xrightarrow[-H_2O]{KOH} [A]$ $\xrightarrow[-H_2O]{H_2SO_4} [B] + K_2SO_4$
The products $[A]$ and $[B]$,respectively,are:

  • A
    $K_2Cr(OH)_6$ and $Cr_2O_3$
  • B
    $K_2CrO_4$ and $Cr_2O_3$
  • C
    $K_2CrO_4$ and $K_2Cr_2O_7$
  • D
    $K_2CrO_4$ and $CrO$

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Consider the following reactions:
$NaCl + K_{2}Cr_{2}O_{7} + H_{2}SO_{4}$ (conc.) $\rightarrow (A) +$ side products
$(A) + NaOH \rightarrow (B) +$ side product
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