Consider the following reactions:K_2Cr_2O_7 + | vedclass

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(A) The reactions are as follows:$1$. $K_2Cr_2O_7 + 4NaCl + 6H_2SO_4 \rightarrow 2CrO_2Cl_2 + 2KHSO_4 + 2NaHSO_4 + 3H_2O$ (Chromyl chloride test).$2$.

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$6$

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(A) The reactions are as follows:$1$. $K_2Cr_2O_7 + 4NaCl + 6H_2SO_4 \rightarrow 2CrO_2Cl_2 + 2KHSO_4 + 2NaHSO_4 + 3H_2O$ (Chromyl chloride test).$2$. $CrO_2Cl_2 + 4NaOH \rightarrow Na_2CrO_4 + 2NaCl + 2H_2O$ (Compound $B$ is $Na_2CrO_4$).$3$. $2Na_2CrO_4 + 2H^+ \rightarrow Na_2Cr_2O_7 + 2Na^+ + H_2O$ (Compound $C$ is $Na_2Cr_2O_7$).In the dichromate ion $(Cr_2O_7^{2-})$,there are two $Cr$ atoms linked by an oxygen bridge $(Cr-O-Cr)$.Each $Cr$ atom is bonded to three terminal oxygen atoms (two double-bonded and one single-bonded with a negative charge).Total terminal oxygen atoms = $3 + 3 = 6$.

Consider the following reactions:
$K_2Cr_2O_7 + NaCl + H_2SO_4 \rightarrow CrO_2Cl_2 + \text{Side Products}$
$CrO_2Cl_{2(Vapour)} + NaOH \rightarrow B + NaCl + H_2O$
$B + H^+ \rightarrow C + H_2O$
The number of terminal $'O'$ atoms present in the compound $'C'$ is $..........$

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Consider the following reactions:$K_2Cr_2O_7 + NaCl + H_2SO_4 \rightarrow CrO_2Cl_2 + \text{Side Products}$$CrO_2Cl_{2(Vapour)} + NaOH \rightarrow B + NaCl + H_2O$$B + H^+ \rightarrow C + H_2O$The number of terminal $'O'$ atoms present in the compound $'C'$ is $..........$