Consider the following sequence of reactions: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction sequence describes the qualitative analysis of Group $V$ cations $(Ca^{2+}, Sr^{2+}, Ba^{2+})$.$1$. When $NH_4Cl(s)$ and $(NH_4)_2CO_

Vedclass · Accepted Answer

$Ba^{2+}(aq.)$

Vedclass · Answer

(D) The reaction sequence describes the qualitative analysis of Group $V$ cations $(Ca^{2+}, Sr^{2+}, Ba^{2+})$.$1$. When $NH_4Cl(s)$ and $(NH_4)_2CO_3$ solution are added,$Ca^{2+}, Sr^{2+},$ and $Ba^{2+}$ form carbonate precipitates $(Q = CaCO_3, SrCO_3, BaCO_3)$. $Mg^{2+}$ does not precipitate in the presence of $NH_4Cl$.$2$. These carbonate precipitates are dissolved in $CH_3COOH$ to form their respective acetates.$3$. Upon adding $(NH_4)_2C_2O_4$,$Ca^{2+}$ and $Sr^{2+}$ form oxalate precipitates $(R = CaC_2O_4, SrC_2O_4)$,whereas $Ba^{2+}$ remains in the filtrate because $BaC_2O_4$ is relatively more soluble.Therefore,$Ba^{2+}$ forms precipitate $Q$ but does not form precipitate $R$ under these conditions.

Consider the following sequence of reactions:
$M^{2+}(aq.)$ $\xrightarrow{NH_4Cl(s) + (NH_4)_2CO_3 \, sol.} Q \downarrow$ $\xrightarrow[\text{Followed by addition of } (NH_4)_2C_2O_4]{CH_3COOH} R \downarrow$
Which of the following cations can form precipitate $Q$ but does not form precipitate $R$?

Similar Questions

Assign $A$,$B$,$C$,$D$ from the given type of reaction: $NiCl_2 (aq) + NaNO_3 (aq) \longrightarrow$ No reaction.

Given below are certain cations. Using inorganic qualitative analysis,arrange them in increasing group number from $0$ to $VI$.
$A$. $Al^{3+}$ $B$. $Cu^{2+}$ $C$. $Ba^{2+}$ $D$. $Co^{2+}$ $E$. $Mg^{2+}$
Choose the correct answer from the options given below.

$A$ solution prepared in conc. $HCl$ sometimes gives white turbidity even in the absence of $1^{st}$ group,when water is added to it. It is due to the presence of

Compound $A$ on borax bead test in reducing flame gives green colour bead. Compound $A$ on treatment with $H_2O_2$ followed by treatment with $Pb(OAc)_2$ gives yellow ppt. The metal ion in the compound $A$ is :

What is the full form of $DMG$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following sequence of reactions:$M^{2+}(aq.)$ $\xrightarrow{NH_4Cl(s) + (NH_4)_2CO_3 \, sol.} Q \downarrow$ $\xrightarrow[\text{Followed by addition of } (NH_4)_2C_2O_4]{CH_3COOH} R \downarrow$Which of the following cations can form precipitate $Q$ but does not form precipitate $R$?