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(C) $1$. $X$ is formed from $C_6H_5CN$ and dissolves in dil. $HCl$. This indicates that $X$ is a basic compound,likely an amine $(C_6H_5CH_2NH_2)$. Th

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$DIBAL-H, H_2O \quad ; LiAlH_4, H_2O$

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(C) $1$. $X$ is formed from $C_6H_5CN$ and dissolves in dil. $HCl$. This indicates that $X$ is a basic compound,likely an amine $(C_6H_5CH_2NH_2)$. The reduction of nitrile to primary amine is achieved by $LiAlH_4$ followed by $H_2O$.$2$. $Y$ is formed from $C_6H_5CN$ and reacts with $2,4-DNP$. This indicates that $Y$ is a carbonyl compound (aldehyde),$C_6H_5CHO$. The partial reduction of nitrile to aldehyde is achieved by $DIBAL-H$ followed by $H_2O$.$3$. Therefore,$A = LiAlH_4, H_2O$ and $B = DIBAL-H, H_2O$.

Consider the following set of reactions. What are $A$ and $B$ respectively?
$Y \xleftarrow{B} C_6H_5CN \xrightarrow{A} X$
($Y$ reacts with $2,4-DNP$)
($X$ dissolves in dil. $HCl$)

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Consider the following set of reactions. What are $A$ and $B$ respectively?$Y \xleftarrow{B} C_6H_5CN \xrightarrow{A} X$($Y$ reacts with $2,4-DNP$)($X$ dissolves in dil. $HCl$)