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(C) Statement $(I)$ is incorrect because the reaction between $NaH$ and $H_2O$ releases hydrogen gas,not oxygen gas: $NaH + H_2O \rightarrow NaOH + H_

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$II$ & $IV$ only

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(C) Statement $(I)$ is incorrect because the reaction between $NaH$ and $H_2O$ releases hydrogen gas,not oxygen gas: $NaH + H_2O \rightarrow NaOH + H_2 \uparrow$. Statement $(II)$ is correct; $CH_4$ and $SiH_4$ have the required number of electrons to form normal covalent bonds,making them electron-precise hydrides. Statement $(III)$ is incorrect; $NH_3$ and $H_2O$ are electron-rich hydrides because they possess lone pairs of electrons on the central atom. Statement $(IV)$ is correct; hydrides of $Be$ and $Mg$ ($BeH_2$ and $MgH_2$) are electron-deficient and exist in polymeric structures. Thus,statements $(II)$ and $(IV)$ are correct.

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