Consider the following statements:Statement-I | vedclass

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(A) Statement-$I$ is correct: $CH_3NH_2$ is more basic than $NH_3$ due to the electron-donating $+I$ effect of the methyl group. $C_6H_5NH_2$ (aniline

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Both statement-$I$ and statement-$II$ are correct

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(A) Statement-$I$ is correct: $CH_3NH_2$ is more basic than $NH_3$ due to the electron-donating $+I$ effect of the methyl group. $C_6H_5NH_2$ (aniline) is less basic than $NH_3$ because the lone pair on nitrogen is delocalized into the benzene ring via resonance.Statement-$II$ is correct: In the aqueous phase, the basicity of ethyl-substituted amines is governed by a combination of inductive effect, solvation effect, and steric hindrance. The observed order for ethylamines is $(C_2H_5)_2NH > (C_2H_5)_3N > C_2H_5NH_2$ due to the greater solvation of the secondary amine and the steric hindrance in the tertiary amine.Therefore, both statements are correct.

Consider the following statements:
Statement-$I$: $CH_3NH_2$ is more basic than $NH_3$, but $C_6H_5NH_2$ is less basic than $NH_3$.
Statement-$II$: The order of basic strength of ethyl-substituted amines in the aqueous phase follows the order $(C_2H_5)_2NH > (C_2H_5)_3N > C_2H_5NH_2$.

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Consider the following statements:Statement-$I$: $CH_3NH_2$ is more basic than $NH_3$, but $C_6H_5NH_2$ is less basic than $NH_3$.Statement-$II$: The order of basic strength of ethyl-substituted amines in the aqueous phase follows the order $(C_2H_5)_2NH > (C_2H_5)_3N > C_2H_5NH_2$.