Consider the following statements:Statement-I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Statement-$I$ is correct: $H_2O_2$ has an oxidation state of $-1$ for oxygen. It can be reduced to $H_2O$ (oxidation state $-2$) or oxidized to $O

Vedclass · Accepted Answer

Statement-$I$ is correct,but statement-$II$ is not correct

Vedclass · Answer

(B) Statement-$I$ is correct: $H_2O_2$ has an oxidation state of $-1$ for oxygen. It can be reduced to $H_2O$ (oxidation state $-2$) or oxidized to $O_2$ (oxidation state $0$),allowing it to act as both an oxidizing and a reducing agent in acidic and basic media.Statement-$II$ is incorrect: $10 \ V \ H_2O_2$ means $1 \ mL$ of $H_2O_2$ solution gives $10 \ mL$ of $O_2$ at $STP$.The decomposition reaction is: $2H_2O_2 ightarrow 2H_2O + O_2$.$2 	imes 34 \ g$ of $H_2O_2$ produces $22400 \ mL$ of $O_2$ at $STP$.So,$22400 \ mL \ O_2$ is produced by $68 \ g \ H_2O_2$.$10 \ mL \ O_2$ is produced by $(68 	imes 10) / 22400 \approx 0.03036 \ g \ H_2O_2$.Since this is in $1 \ mL$ of solution,the concentration is $0.03036 \ g/mL$,which is $3.03\% \ (w/v)$. The statement claims $6\%$,which is incorrect.

Consider the following statements:
Statement-$I$: $H_2O_2$ acts as an oxidising as well as a reducing agent in both acidic and basic media.
Statement-$II$: $10 \ V \ H_2O_2$ sample means it contains $3.03\% \ (w/v) \ H_2O_2$.

Similar Questions

Which one of the following reactions represents the oxidising property of $H_2O_2$?

What is the amount of $H_2O_2$ in grams present in $1 \ L$ of $1.5 \ N$ $H_2O_2$ solution?

Decolourisation of acidified potassium permanganate occurs when $H_2O_2$ is added to it,this is due to

The $H-O-O$ bond angle in $H_2O_2$ is ............. $^o$

$H_2O_2$ restores the color of old lead paintings,blackened by the action of $H_2S$ gas by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following statements:Statement-$I$: $H_2O_2$ acts as an oxidising as well as a reducing agent in both acidic and basic media.Statement-$II$: $10 \ V \ H_2O_2$ sample means it contains $3.03\% \ (w/v) \ H_2O_2$.