Consider the galvanic cell: A_{(s)} | A_{(aq) | vedclass

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Question

(B) In a galvanic cell represented as $Anode | Anode_{electrolyte} || Cathode_{electrolyte} | Cathode$,the oxidation occurs at the anode and reduction

Vedclass · Accepted Answer

$A_{(s)} + 2 B_{(aq)}^{+} \rightarrow A_{(aq)}^{+2} + 2 B_{(s)}$

Vedclass · Answer

(B) In a galvanic cell represented as $Anode | Anode_{electrolyte} || Cathode_{electrolyte} | Cathode$,the oxidation occurs at the anode and reduction occurs at the cathode. For the given cell $A_{(s)} | A_{(aq)}^{+2} || B_{(aq)}^{+} | B_{(s)}$: Anode reaction (Oxidation): $A_{(s)} \rightarrow A_{(aq)}^{+2} + 2e^-$. Cathode reaction (Reduction): $B_{(aq)}^{+} + e^- \rightarrow B_{(s)}$. To balance the electrons,multiply the cathode reaction by $2$: $2 B_{(aq)}^{+} + 2e^- \rightarrow 2 B_{(s)}$. Adding both half-reactions: $A_{(s)} + 2 B_{(aq)}^{+} \rightarrow A_{(aq)}^{+2} + 2 B_{(s)}$. Thus,the correct option is $B$.

Consider the galvanic cell: $A_{(s)} | A_{(aq)}^{+2} || B_{(aq)}^{+} | B_{(s)}$. If the $EMF$ of the cell is positive,identify the correct cell reaction from the following.

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