Consider the given sequence of reactions.C_2H | vedclass

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(A) The reaction $C_2H_6 + \frac{3}{2}O_2 \xrightarrow[(CH_3COO)_2Mn]{\Delta} CH_3COOH$ produces $X = CH_3COOH$ (acetic acid).The reaction $CH_3COOH +

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$C_2H_6, CO_2$

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(A) The reaction $C_2H_6 + \frac{3}{2}O_2 \xrightarrow[(CH_3COO)_2Mn]{\Delta} CH_3COOH$ produces $X = CH_3COOH$ (acetic acid).The reaction $CH_3COOH + NaOH ightarrow CH_3COONa + H_2O$ produces $Y = CH_3COONa$ (sodium acetate).Kolbe's electrolysis of aqueous sodium acetate $(CH_3COONa)$ is represented as:$2CH_3COONa + 2H_2O \xrightarrow{	ext{electrolysis}} CH_3-CH_3 + 2CO_2 + H_2 + 2NaOH$.At the anode,the products formed are ethane $(C_2H_6)$ and carbon dioxide $(CO_2)$.Thus,$P$ and $Q$ are $C_2H_6$ and $CO_2$ respectively.

Consider the given sequence of reactions.
$C_2H_6 + \frac{3}{2}O_2$ $\xrightarrow[\Delta]{(CH_3COO)_2Mn} X$ $\xrightarrow{NaOH} Y$
Electrolysis of aqueous solution of $Y$ gives gases $P$ and $Q$ at anode. $P$ and $Q$ are respectively.

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Consider the given sequence of reactions.$C_2H_6 + \frac{3}{2}O_2$ $\xrightarrow[\Delta]{(CH_3COO)_2Mn} X$ $\xrightarrow{NaOH} Y$Electrolysis of aqueous solution of $Y$ gives gases $P$ and $Q$ at anode. $P$ and $Q$ are respectively.