Consider the graphs (I),(II) and (III). The c | vedclass

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(C) Graph $(I)$ shows the variation of the amount of gas adsorbed with temperature for physical adsorption (physiosorption). In physiosorption,adsorpt

Vedclass · Accepted Answer

$(I)$ is physiosorption,$(II)$ is chemisorption and $T_1 > T_2$

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(C) Graph $(I)$ shows the variation of the amount of gas adsorbed with temperature for physical adsorption (physiosorption). In physiosorption,adsorption decreases with an increase in temperature because it is an exothermic process.Graph $(II)$ shows the variation for chemical adsorption (chemisorption). Chemisorption initially increases with temperature due to the activation energy requirement and then decreases at higher temperatures.Graph $(III)$ represents the Freundlich adsorption isotherm,where the amount of gas adsorbed increases with pressure. For physical adsorption,adsorption decreases as temperature increases. Since the curve for $T_1$ is below the curve for $T_2$ at the same pressure,it implies $T_1 > T_2$.

Consider the graphs $(I)$,$(II)$ and $(III)$. The correct statement related to the graphs is/are:

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