Consider the nuclear fission Ne^{20} to 2He^4 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The energy released $(Q)$ in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding

Vedclass · Accepted Answer

None of these.

Vedclass · Answer

(D) The energy released $(Q)$ in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding energy of the reactants.$Q = (	ext{Total B.E. of products}) - (	ext{Total B.E. of reactants})$$Q = (2 	imes 4 	imes 7.07 + 12 	imes 7.86) - (20 	imes 8.03)$$Q = (56.56 + 94.32) - 160.6$$Q = 150.88 - 160.6$$Q = -9.72\, MeV$Since the $Q$ value is negative,the reaction is endothermic,meaning $9.72\, MeV$ of energy must be supplied to the system for the reaction to occur. Therefore,none of the given options are correct.

Consider the nuclear fission $Ne^{20} \to 2He^4 + C^{12}$. Given that the binding energy per nucleon of $Ne^{20}$,$He^4$,and $C^{12}$ are,respectively,$8.03\, MeV$,$7.07\, MeV$,and $7.86\, MeV$,identify the correct statement.

Similar Questions

An $\alpha$-particle of energy $E$ is liberated during the decay of a nucleus of mass number $236$. The total energy released in this process is

How much mass of uranium must be destroyed per minute to operate a nuclear reactor of $600\,MW$?

What is a nuclear reactor? Explain its principle,construction,and working.

In a fast breeder atomic reactor,.......

During the nuclear fusion reaction,

Vedclass Test Series

Exam Paper Generator

Online Exam Module