Consider the nuclear reaction X^{200} rightar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy released in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding energy

Vedclass · Accepted Answer

$160$

Vedclass · Answer

(B) The energy released in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding energy of the reactants.Total binding energy of reactant $X = 200 	imes 7.4 \, MeV = 1480 \, MeV$.Total binding energy of products $A$ and $B = (110 	imes 8.2 \, MeV) + (90 	imes 8.2 \, MeV) = (110 + 90) 	imes 8.2 \, MeV = 200 	imes 8.2 \, MeV = 1640 \, MeV$.Energy released $Q = (	ext{Total binding energy of products}) - (	ext{Total binding energy of reactants})$.$Q = 1640 \, MeV - 1480 \, MeV = 160 \, MeV$.

Consider the nuclear reaction $X^{200} \rightarrow A^{110} + B^{90}$. If the binding energy per nucleon for $X, A,$ and $B$ is $7.4 \, MeV, 8.2 \, MeV,$ and $8.2 \, MeV$ respectively, what is the energy released in $MeV$?

Similar Questions

The binding energy per nucleon versus mass number curve is shown in the figure. $W, X, Y$ and $Z$ are four nuclei on the curve. In which process is energy released?

If mass-energy equivalence is taken into account,when water is cooled to form ice,the mass of water should

The binding energy per nucleon is maximum in the case of

The binding energy per nucleon of $^{16}O$ is $7.97 \ \text{MeV}$ and that of $^{17}O$ is $7.75 \ \text{MeV}$. The energy (in $\text{MeV}$) required to remove a neutron from $^{17}O$ is:

$M_p$ denotes the mass of a proton and $M_n$ that of a neutron. $A$ given nucleus,of binding energy $B$,contains $Z$ protons and $N$ neutrons. The mass $M(N, Z)$ of the nucleus is given by ($c$ is the velocity of light):

Vedclass Test Series

Exam Paper Generator

Online Exam Module