Consider the reaction K_2[Ni(CN)_4] + 4K + 4N | vedclass

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(A) The reaction is $K_2[Ni(CN)_4] + 4K + 4NH_3 	o K_4[Ni(NH_3)_4] + 4KCN$.Complex $A$ is $K_4[Ni(NH_3)_4]$.In $K_4[Ni(NH_3)_4]$,the oxidation state

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Complex is $sp^3$ hybridised & diamagnetic

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(A) The reaction is $K_2[Ni(CN)_4] + 4K + 4NH_3 	o K_4[Ni(NH_3)_4] + 4KCN$.Complex $A$ is $K_4[Ni(NH_3)_4]$.In $K_4[Ni(NH_3)_4]$,the oxidation state of $Ni$ is $0$ ($d^{10}$ configuration).Since $Ni(0)$ has a $d^{10}$ configuration,all $d$-orbitals are filled.Therefore,it undergoes $sp^3$ hybridisation to form a tetrahedral geometry.Since all electrons are paired in the $d^{10}$ configuration,the complex is diamagnetic.Thus,the complex is $sp^3$ hybridised and diamagnetic.

Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).
Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.

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Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.