Consider two rods $1$ and $2$ of same length $L$. They have different specific heats $(C_1, C_2)$, thermal conductivities $(K_1, K_2)$ and area of cross-section $(A_1, A_2)$ respectively. Both the rods have temperatures $(T_1, T_2)$ at their ends. If their rate of loss of heat due to conduction is equal, then

  • A
    $A_1K_2 = A_2K_1$
  • B
    $A_1K_1 = A_2K_2$
  • C
    $\frac{A_1K_1}{C_1} = \frac{A_2K_2}{C_2}$
  • D
    $\frac{A_1K_2}{C_1} = \frac{A_2K_1}{C_2}$

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