Construct $\Delta ABC$ in which $BC = 6\,cm$,$\angle B = 45^{\circ}$ and $AB - AC = 1.5\,cm$. Write the steps of construction.
(N/A) Steps of construction:
$1$. Draw a line segment $BC = 6\,cm$.
$2$. At point $B$,construct an angle $\angle XBC = 45^{\circ}$.
$3$. Cut a line segment $BD = 1.5\,cm$ from the ray $BX$.
$4$. Join $DC$.
$5$. Draw the perpendicular bisector of $DC$,which intersects $BX$ at a point $A$.
$6$. Join $AC$. Thus,$\Delta ABC$ is the required triangle.
$1$. Draw a line segment $BC = 6\,cm$.
$2$. At point $B$,construct an angle $\angle XBC = 45^{\circ}$.
$3$. Cut a line segment $BD = 1.5\,cm$ from the ray $BX$.
$4$. Join $DC$.
$5$. Draw the perpendicular bisector of $DC$,which intersects $BX$ at a point $A$.
$6$. Join $AC$. Thus,$\Delta ABC$ is the required triangle.
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