Construct a triangle $ABC$,in which $\angle B = 60^{\circ}$,$\angle C = 45^{\circ}$ and $AB + BC + CA = 11 \, cm$.

(N/A) $1.$ Draw a line segment $PQ = 11 \, cm$ such that $PQ = AB + BC + CA$.
$2.$ At point $P$,construct an angle of $\frac{60^{\circ}}{2} = 30^{\circ}$ and at point $Q$,construct an angle of $\frac{45^{\circ}}{2} = 22.5^{\circ}$.
$3.$ Let these angle bisectors intersect at point $A$.
$4.$ Draw the perpendicular bisector of $AP$,which intersects $PQ$ at $B$.
$5.$ Draw the perpendicular bisector of $AQ$,which intersects $PQ$ at $C$.
$6.$ Join $AB$ and $AC$. Thus,$ABC$ is the required triangle.