Construct a triangle whose sides are $3.6 \, cm$,$3.0 \, cm$,and $4.8 \, cm$. Bisect the smallest angle and measure each part. Write the steps of construction.

(N/A) Step $1$: Draw a line segment $AB = 4.8 \, cm$.
Step $2$: Taking $A$ as the center and radius $3.0 \, cm$,draw an arc. Taking $B$ as the center and radius $3.6 \, cm$,draw another arc that intersects the previous arc at point $C$.
Step $3$: Join $CA$ and $CB$ to obtain the required triangle $ABC$.
Step $4$: Measure all internal angles. The smallest angle is $\angle ABC$ (opposite to the shortest side $AC = 3.0 \, cm$).
Step $5$: To bisect $\angle ABC$,take any radius and with center $B$,draw an arc that intersects $AB$ at $P$ and $BC$ at $Q$.
Step $6$: With the same radius and centers $P$ and $Q$,draw two arcs that intersect each other at point $R$.
Step $7$: Join $BR$ and extend it to intersect $AC$ at point $D$. $BD$ is the angle bisector of $\angle ABC$.