Convert the following pressure values into atmosphere $(atm)$:
$(a)$ $735 \ torr$
$(b)$ $985 \ mbar$
$(c)$ $1.42 \times 10^5 \ Nm^{-2}$

(N/A) The conversion factors are: $1 \ atm = 760 \ torr$,$1 \ atm = 1013.25 \ mbar$,and $1 \ atm = 1.01325 \times 10^5 \ Nm^{-2}$.
$(a)$ $735 \ torr = \frac{735}{760} \ atm \approx 0.967 \ atm$.
$(b)$ $985 \ mbar = \frac{985}{1013.25} \ atm \approx 0.972 \ atm$.
$(c)$ $1.42 \times 10^5 \ Nm^{-2} = \frac{1.42 \times 10^5}{1.01325 \times 10^5} \ atm \approx 1.401 \ atm$.