Copper sulphate dissolves in excess of KCN to | vedclass

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Question

(C) When $CuSO_4$ reacts with $KCN$,it first forms a precipitate of cupric cyanide $(Cu(CN)_2)$,which is unstable and decomposes to form cuprous cyani

Vedclass · Accepted Answer

$[Cu(CN)_4]^{3-}$

Vedclass · Answer

(C) When $CuSO_4$ reacts with $KCN$,it first forms a precipitate of cupric cyanide $(Cu(CN)_2)$,which is unstable and decomposes to form cuprous cyanide $(Cu_2(CN)_2)$ and cyanogen gas $((CN)_2)$.$2CuSO_4 + 4KCN \rightarrow 2Cu(CN)_2 + 2K_2SO_4$$2Cu(CN)_2 \rightarrow Cu_2(CN)_2 + (CN)_2$The cuprous cyanide $(Cu_2(CN)_2)$ then dissolves in excess $KCN$ to form the stable soluble complex potassium tetracyanocuprate$(I)$,$K_3[Cu(CN)_4]$.$Cu_2(CN)_2 + 6KCN \rightarrow 2K_3[Cu(CN)_4]$Overall reaction:$2CuSO_4 + 10KCN \rightarrow 2K_3[Cu(CN)_4] + 2K_2SO_4 + (CN)_2$

Copper sulphate dissolves in excess of $KCN$ to give

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