The correct order of H-bond strength for the | vedclass

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(A) The strength of a hydrogen bond depends on the electronegativity difference and the charge density of the atoms involved.$1$. The interaction $a$

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$a > b > d > c$

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(A) The strength of a hydrogen bond depends on the electronegativity difference and the charge density of the atoms involved.$1$. The interaction $a$ $(F^{-}H...F^{-})$ is a symmetric,very strong hydrogen bond (often called a low-barrier hydrogen bond) due to the high electronegativity of $F$ and the negative charge,making it the strongest.$2$. The interaction $b$ $(F^{-}H...F)$ involves a neutral $F$ atom,making it weaker than $a$ but stronger than interactions involving $O$ and $N$.$3$. Comparing $c$ $(O^{-}H...N)$ and $d$ $(O^{-}H...O)$,the electronegativity of $O$ $(3.44)$ is greater than that of $N$ $(3.04)$. Thus,the $O-H...O$ interaction $(d)$ is stronger than the $O-H...N$ interaction $(c)$.Therefore,the correct order of strength is $a > b > d > c$.

The correct order of $H$-bond strength for the following interactions is:
$a: F^{-}H...F^{-}$
$b: F^{-}H...F$
$c: O^{-}H...N$
$d: O^{-}H...O$
Identify the correct order of strength.

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The correct order of $H$-bond strength for the following interactions is:$a: F^{-}H...F^{-}$$b: F^{-}H...F$$c: O^{-}H...N$$d: O^{-}H...O$Identify the correct order of strength.