Correct order of 3^{rd} Ionisation energy of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The $3^{rd}$ ionisation energy corresponds to the removal of an electron from the $M^{2+}$ ion.The electronic configurations of the $M^{2+}$ ions

Vedclass · Accepted Answer

$O > C > N > B$

Vedclass · Answer

(B) The $3^{rd}$ ionisation energy corresponds to the removal of an electron from the $M^{2+}$ ion.The electronic configurations of the $M^{2+}$ ions are:$B^{2+} (Z=5): 1s^2 2s^1$$C^{2+} (Z=6): 1s^2 2s^2$$N^{2+} (Z=7): 1s^2 2s^2 2p^1$$O^{2+} (Z=8): 1s^2 2s^2 2p^2$Comparing these:$B^{2+}$ has a single electron in the $2s$ orbital,which is relatively easy to remove.$C^{2+}$ has a stable,fully filled $2s^2$ subshell,making it very difficult to remove an electron.$N^{2+}$ and $O^{2+}$ have electrons in the $2p$ subshell.Due to higher effective nuclear charge,$O^{2+}$ has a higher $3^{rd}$ $IE$ than $N^{2+}$.Comparing $C^{2+}$ and $N^{2+}$,the removal of an electron from the stable $2s^2$ configuration of $C^{2+}$ requires more energy than from the $2p^1$ configuration of $N^{2+}$.Thus,the order is $O > C > N > B$.

Process	Condition
$(I)$ Adiabatic	$(A)$ $\Delta W = 0$
$(II)$ Isothermal	$(B)$ $\Delta Q = 0$
$(III)$ Isochoric	$(C)$ $\Delta U \neq 0, \Delta W \neq 0, \Delta Q \neq 0$
$(IV)$ Isobaric	$(D)$ $\Delta U = 0$

Correct order of $3^{rd}$ Ionisation energy of $B, C, N$ and $O$ will be

Similar Questions

Which one is an incorrect statement?

Let electronegativity,ionisation energy and electron affinity be represented as $EN$,$IP$ and $EA$ respectively. Which one of the following equations is correct according to Mulliken?

The maximum value of $x^4 e^{-x^2}$ is

$A$ body is thrown vertically upwards and reaches its maximum height in $t$ seconds. The total time from the time of projection to reach a point at half of its maximum height while returning (in seconds) is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module