The correct order of the rate of EAS (electro | vedclass

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Question

(A) The rate of electrophilic aromatic substitution $(EAS)$ is directly proportional to the electron density in the benzene ring. Groups that donate e

Vedclass · Accepted Answer

$c > d > b > a$

Vedclass · Answer

(A) The rate of electrophilic aromatic substitution $(EAS)$ is directly proportional to the electron density in the benzene ring. Groups that donate electrons (via $+I$ or $+M$ effects) increase the rate,while groups that withdraw electrons (via $-I$ or $-M$ effects) decrease the rate. $(a)$ Nitrobenzene $(-NO_2)$: Strong electron-withdrawing group ($-M$ and $-I$ effects),strongly deactivates the ring. $(b)$ Chlorobenzene $(-Cl)$: Electron-withdrawing group ($-I$ effect dominates over $+M$ effect),deactivates the ring. $(c)$ Toluene $(-CH_3)$: Electron-donating group ($+I$ and hyperconjugation),activates the ring. $(d)$ Benzene: Reference compound. Therefore,the order of reactivity is: Toluene $(c)$ > Benzene $(d)$ > Chlorobenzene $(b)$ > Nitrobenzene $(a)$. The correct order is $c > d > b > a$.

The correct order of the rate of $EAS$ (electrophilic aromatic substitution) for the following compounds is:

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